kalani7732 kalani7732
  • 01-08-2018
  • Mathematics
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Someone please answer this is so hard for me I don’t know where to start or how to answer :(

Someone please answer this is so hard for me I dont know where to start or how to answer class=

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agaue agaue
  • 01-08-2018

The given triangle is a right angle .

In this triangle for angle A side AC is adjacent side ,BC is opposite side and AB is hypotenuse.

Sin of any angle is the ratio of opposite and hypotenuse .

[tex] sin=\frac{opposite}{hypotenuse} [/tex]

Substituting the values of opposite and hypotenuse

SinA=[tex] \frac{12}{37} [/tex]

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