melindamackay83 melindamackay83

04-01-2019
Mathematics

contestada

At the pet fair Darlene’s dog weighed five times as much as leaders dog. Together the dogs weighed 84 pounds how much did each dog weigh?

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musiclover10045 musiclover10045

04-01-2019

Answer:

Let the weight of the leader dog = X

Then Darlene's dog weighs = 5X ( fives times as much)

Now add both together to equal 84 pounds:

5X + X = 84

Simplify:

6x = 84

Divide both sides by 6:

x = 84 / 6

x = 14

The leader dog weighs 14 pounds.

Darlene's dog weighs 70 pounds.

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