skrishnarajpet
skrishnarajpet skrishnarajpet
  • 01-03-2020
  • Mathematics
contestada

solve the equation
b^2+36=0

(not 6i)

Respuesta :

MIRAGEE
MIRAGEE MIRAGEE
  • 01-03-2020

I hope this helps you

b^2= - 36

b^2= - 1.6^2

b^2= i^2.(+,-6)^2

b=6i

b= - 6i

or b isn't real number there is no solution....

Answer Link
tramserran
tramserran tramserran
  • 01-03-2020

Answer:  ±6i

Step-by-step explanation:

[tex]b^2+36=0\\\\b^2\qquad =-36\\\\\sqrt{b^2}\quad =\sqrt{-36}\\\\|b|\qquad =\sqrt{-1\cdot 6 \cdot 6}\\\\|b|\qquad =6i\\\\\large\boxed{b \qquad=\pm 6i}\\[/tex]

Answer Link

Otras preguntas

What is a tragic impulse? an uncharacteristic strength a weakness in a central character a character’s sense of hopelessness a noble act by the tragic hero
Help fill in the answers and are my answers rigt
In a proper webpage, which tag holds all of a webpages visible HTML? Html Head Body Link Scriptdoctype
find the slope and y-intercept of the line formed by the equation 2y = 4x - 6
what is the difference between a letter written by an eyewitness to an event and an encyclopedia entry about the same event ?
x/-3-50=0 PLEASE HELP
in the following figure lines j and k are parallel and are cut by transversal t Thanks
If F = {(2, 5), (3, 4), (4, 6), (2, 1), (7, 2)}, then F is a function. true or false
please help me thank you!!!!!
What's the answer to 5(-2x+5)=-6