Respuesta :

LammettHash
If [tex]x[/tex] is one of the component integers, then the next consecutive integer is [tex]x+1[/tex], the following one is [tex]x+2[/tex] and so on.

This means the sum can be written as
[tex]x+(x+1)+(x+2)+(x+3)=114[/tex]

Solving for [tex]x[/tex], you find that [tex]x=27[/tex], so the integers are [tex]27,28,29,30[/tex].

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