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01-02-2017
Mathematics

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evaluate the limit as t approaches inifinity of [tex] \lim_{t \to \infty} \frac{ \sqrt{t}+ t^{2} }{8t- t^{2} } [/tex]

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LammettHash LammettHash

01-02-2017

[tex]\displaystyle\lim_{t\to\infty}\frac{\sqrt t+t^2}{8t-t^2}=\lim_{t\to\infty}\frac{\dfrac1{t^{3/2}}+1}{\dfrac8t-1}=\frac1{-1}=-1[/tex]

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