Turp1999 Turp1999
  • 03-02-2017
  • Mathematics
contestada

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3).

-40
-38
7

Respuesta :

nobrains
nobrains nobrains
  • 03-02-2017
[tex]f(x) = x^2 + 1 \\ g(x) = 3x + 1[/tex]

You can do this in parts.
[tex]f(-1) = (-1)^2 + 1 = 1 + 1 = 2[/tex]
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38

Or you can do this as one big chunk.
f(-1) + 5g(-3)
[tex]=[(-1)^2+1] + 5[3(-3) + 1] \\ = (2) + 5(-9 + 1) \\ = 2 + 5(-8) \\ = 2 - 40 \\ = -38[/tex]
Answer Link
apologiabiology
apologiabiology apologiabiology
  • 03-02-2017
easy

f(-1)=(-1)²+1
f(-1)=1+1
f(-1)=2

5g(-3)=5(3(-3)+1)
5g(-3)=5(-9+1)
5g(-3)=5(-8)
5g(-3)=-40


f(-1)+5g(-3)=2-40=-38


answer is -38
Answer Link

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