Given the equation
[tex]v(n)=14*b^n[/tex]
where
v=value
b=base
n=weeks
since we are ask for the wwekly report n=1
since we are ask for a percentage we need to compare with n=0
then
[tex]v(0)=14*b^0[/tex][tex]v(0)=14[/tex]
now
[tex]v(1)=14*b^1[/tex]
Proving
b=0.84
[tex]v(1)=14*0.84^1=11.76[/tex]
Not correct with the shown statement
-b=1.06
[tex]v(1)=14*1.06^1=14.84[/tex][tex]14.86-14=0.84[/tex][tex]14*\frac{6}{100}=0.84[/tex]
the 6% of 14 is 0.84 then
a base of b=1.06 gives a growth rate of 6%
Correct answer option B
